ValinK16408 ValinK16408

30-10-2022
Mathematics

contestada

laws of exponent : multiplication and power to a power(x2y3) ⁵

Respuesta :

RomariC553095 RomariC553095

30-10-2022

we have

[tex]\mleft(x^2y^3\mright)^5[/tex]

Apply the laws of exponent

[tex](x^2y^3)^5=(x^2)^5\cdot(y^3)^5[/tex][tex](x^2)^5\cdot(y^3)^5=x^{(2\cdot5)}\cdot y^{(3\cdot5)}[/tex][tex]x^{(10)}\cdot y^{(15)}[/tex]

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