Given the quadratic equation :
[tex]x^2+16x-5[/tex]It is required to make a complete square
The coefficient of x = 16
so, we will add : the square of ( half of the coefficient x )
so, half of 16 = 0.5 * 16 = 8
Square of 8 = 64
So, the complete square will be as following ;
[tex]\begin{gathered} x^2+16x-5+64-64 \\ =x^2+16x+64-5-64 \\ =(x^2+16x+64)+(-5-64) \\ =(x+8)^2+(-69) \\ \\ =(x+8)^2-69 \end{gathered}[/tex]