Given the inequality:
[tex]x^2>-9x-18[/tex]Solve for x as follows:
[tex]\begin{gathered} x^2+9x+18>0 \\ (x+3)(x+6)>0 \\ x+3=0\rightarrow x=-3 \\ x+6=0\rightarrow x=-6 \\ So,\text{ } \\ x>-3,x<-6 \end{gathered}[/tex]So, the answer will be option C) x < -6 and x > -3
