Running at 2.0 m/s, Marty, the 45.0-kg quarterback, collides with Biff, the 90.0-kg tackle, who is traveling at 7.0 m/s in the other direction. Upon collision, Biff continues to travel forward at 1.0 m/s. How fast is Marty knocked backwards?

Respuesta :

ANSWER:

10 m/s backward

STEP-BY-STEP EXPLANATION:

We have that for the change of momentum, the following formula:

[tex]m_1\cdot v_{11}+m_2\cdot v_{12}=m_1\cdot v_{12}+m_2\cdot v_{22}[/tex]

We substitute, the known values, to calculate the value of Marty's velocity:

[tex]\begin{gathered} 45\cdot-2+90\cdot7=45\cdot-v_{12}+90\cdot1 \\ v_{12}=\frac{45\cdot-2+90\cdot7-90\cdot1}{-45} \\ v_{12}=\frac{-90+630-90}{-45} \\ v_{12}=\frac{450}{-45} \\ v_{12}=-10\text{ m/s} \end{gathered}[/tex]

Therefore, Marty's velocity is 10 m/s backward.