The standard for of a parabola equation is given by:
[tex]\begin{gathered} (y-k)^2=4p(x-h) \\ or \\ (x-h)^2=4p(y-k) \end{gathered}[/tex]
Considering the first form with h = 3, p = 1/16 and k = -4 we have:
[tex]\begin{gathered} (y+4)^2=\frac{4}{16}(x-3) \\ (x-3)=4(y+4)^2 \end{gathered}[/tex]
Therefore, the equation represents a parabola where h = 3, k = -4 and p = 1/16
