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The circle given by *2 + y2 - 4x -10=0 can be written in standard form 2. like this: (x - h) + y2 = 14 What is the value of h in this equation?

The circle given by 2 y2 4x 100 can be written in standard form 2 like this x h y2 14 What is the value of h in this equation class=

Respuesta :

Given the equation of the circle:

[tex]x^2+y^2-4x-10=0[/tex]

We will complete the square for the terms of x

so,

[tex]\begin{gathered} (x^2-4x)+y^2=10 \\ (x^2-4x+4)+y^2=10+4 \\ (x-2)^2+y^2=14 \end{gathered}[/tex]

compare the final result with the equation:

[tex](x-h)^2+y^2=14[/tex]

So, the value of h = 2

So, the answer will be:

[tex]h=2[/tex]

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