To answer this question we will use the following slope-point formula for the equation of a line:
[tex]y-y_1=m(x-x_1).[/tex]Therefore, the equation of the line that has a slope of 3 and passes through (2,2) is:
[tex]y-2=3(x-2).[/tex]Simplifying the above result we get:
[tex]y-2=3x-6.[/tex]Adding 2 to the above equation we get:
[tex]\begin{gathered} y-2+2=3x-6+2, \\ y=3x-4. \end{gathered}[/tex]From the last equation, we get that the y-intercept of the line is (0,-4).
Since the graph of the line also passes through (2,2) we get that its graph is:
Answer:
