y + 4 = 1/3(x + 9)
The formula for finding the equation of a line perpenicular to another line and passing through a point (x1, y1) is expressed as
[tex]y-y_1=-\frac{1}{m}(x-x_1)[/tex]where:
• m is sthe ,slope of the given line
,• (x1, y1) is the ,point on the line
Determine the slope of the given line
Given the equation y = -3x + 6, the slope of the line is -3
Substitute the slope and the given point into the formula as shown:
[tex]\begin{gathered} y-(-4)=\frac{-1}{-3}(x-(-9)) \\ y+4=\frac{1}{3}(x+9) \\ \end{gathered}[/tex]Hence the required equation in point-slope form is y + 4 = 1/3(x + 9)
