Answer:
151.93 bushels
Explanation:
First, let's find the volume of the truncated cone using the following equation
[tex]V=\frac{1}{3}\pi h(r^2+rR+R^2)[/tex]
Where h is the height of the cone, r is the smallest radio and R is the largest radio. So, replacing h = 4 ft, r = 1.5 ft and R = 4.5 ft, we get:
[tex]\begin{gathered} V=\frac{1}{3}(3.14)(4)((1.5)^2+(1.5)(4.5)+(4.5)^2) \\ V=\frac{1}{3}(3.14)(4)(29.25) \\ V=122.52ft^3 \end{gathered}[/tex]
Because the radius is half the diameter, so r = 3ft/2 = 1.5 ft and R = 9ft/2 = 4.5 ft.
Now, we know the volume in cubic feet. To find the volume in bushels, we will use the conversion factor 1 ft³ = 1.24 bushels.
[tex]122.52ft^3\times\frac{1.24\text{ bushels}}{1ft^3}=151.93\text{ bushels}[/tex]
Therefore, the answer is 151.93 bushels
