The line:
[tex]-2x+3y=-4[/tex]can be written as:
[tex]\begin{gathered} -2x+3y=-4 \\ 3y=2x-4 \\ y=\frac{2}{3}x-\frac{4}{3} \end{gathered}[/tex]from this form we notice that its slope is 2/3.
We know that two lines are parallel if and only if their slopes are equal, this measn the lie we are looking for has slope 2/3 also.
Once we know the slope of the second line and since we know a point of it we can use the equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]Plugging the values we have that the equation we are looking for is:
[tex]y-3=\frac{2}{3}(x-1)[/tex]