Respuesta :

We have the following:

The formula that corresponds to the calculation of the population is as follows

[tex]P=A\cdot(1+r)^t[/tex]

Where A is the population of 952 108 000 inhabitants, r is the growth rate and t is the time elapsed

a.

2000

[tex]\begin{gathered} t=2000-1996=4 \\ P=952,108,000\cdot(1+0.013)^4=1002591447.8\cong1,002,600,000 \end{gathered}[/tex]

2010

[tex]\begin{gathered} t=2010-1996=14 \\ P=952,108,000\cdot(1+0.013)^{14}=1140823475.4\cong1,140,800,000 \end{gathered}[/tex]

b.

In this case what we must do is replace by 10, which is the equivalent in years of a decade in the part of the equation that corresponds to growth

[tex]\begin{gathered} (1+0.013)^{10}=1.13787 \\ 1.13787-1=0.1378 \end{gathered}[/tex]

That is, the growth is approximately 13.78%

c.

In this case, we must calculate until 2000 with the percentage of 1.3% and then from 2000 until 2010 calculate with the new growth rate

A then would be the population calculated in part a, that is, 1,002,600,000 and t would be 10 (2010 - 2000)

replacing

[tex]P=1,002,600,000\cdot(1+0.01)^{10}=1107494142.9\cong1,107,500,000[/tex]

Therefore with the new growth rate the population in India in 2010 would be 1,107,500,000