The surface area is the sum of the area of the square plus the area of the 4 equal triangles. So, we need to find the area of one triangle multiply by 4 and add the area of the square.
Then, the area of one triangle is
[tex]\begin{gathered} A_T=\frac{1}{2}(3.4)(4.4) \\ A_T=7.48cm^2 \end{gathered}[/tex]
and the area of the square is
[tex]\begin{gathered} A_S=(3.4)^2 \\ A_S=11.56cm^2 \end{gathered}[/tex]
Then, the surface S is
[tex]\begin{gathered} S=4\times A_T+A_S \\ S=4\times7.48+11.56 \\ S=41.48cm^2 \end{gathered}[/tex]
And the answer is 41.48 centimeters squared.
