[tex]C.\:42[/tex]
1) Since the area of a Rhombus is given by the product of their diagonals over 2. We can tell that:
[tex]\begin{gathered} A=\frac{AC\times BD}{2} \\ \\ 273=\frac{13BD}{2} \\ \\ 13BD=546 \\ \\ BD=\frac{546}{13} \\ \\ BD=42 \end{gathered}[/tex]
2) Thus, we can tell that the length of BD is 42
