Solution:
The quadaratic equation is given below as
[tex]x^2+4x=18[/tex]
Step 1:
Take half of the x term and square it
[tex](4\times\frac{1}{2})^2=2^2=4[/tex]
Then add the result to both sides
Hence, We will have
[tex]x^2+4x+4=18+4[/tex]
Step 2:
Rewrite the perfect square on the left
Hence,
We will have
[tex](x+2)^2=22[/tex]
Step 3:
Take the square root of both sides, we will have
[tex]\begin{gathered} x+2=\sqrt{22} \\ x+2=\pm4.7 \end{gathered}[/tex]
Step 4:
Isolate the x on the left side and
solve for x (1)
[tex]\begin{gathered} x+2=4.7 \\ x=4.7-2 \\ x=2.7 \\ \\ x+2=-4.7 \\ x=-4.7-2 \\ x=-6.7 \end{gathered}[/tex]
Hence,
The final answers will be shown in the image below
