Jack and Jane leave their home traveling in opposite directions on a straight road. Jack drives 20 mph faster than Jane. After 4 hours, they are 250 miles apart. What Jack's rate is and what Jane's rate is

Respuesta :

Answer:

Jane's rate is 21.25 mph.

Jack's rate is 41.25mph

Explanation:

Let x represent Jane's speed.

Jack's speed will be x+20.

Their combined speed is;

[tex]x+x+20=2x+20[/tex]

After 4 hours, their combined distance covered is 250 miles;

[tex]\begin{gathered} 4(2x+20)=250 \\ 8x+80=250 \end{gathered}[/tex]

solving for x;

[tex]\begin{gathered} 8x=250-80 \\ 8x=170 \\ x=\frac{170}{8} \\ x=21.25\text{ mph} \end{gathered}[/tex]

Jane's rate is 21.25 mph.

Since jack's rate is 20 mph faster than Jane's rate.

Jack's rate is;

[tex]\begin{gathered} 21.25+20 \\ =41.25\text{mph} \end{gathered}[/tex]

Jack's rate is 41.25mph