contestada

Kerosene is supplied to a tap from a tank in which the kerosene level is 1.5 m above the tap. If the density of kerosene is 800 kg/m3. Calculate pressure of the kerosene at the tap.

Respuesta :

ANSWER

[tex]\begin{equation*} 11,760\text{ }N\/m^2 \end{equation*}[/tex]

EXPLANATION

To find the pressure of the kerosene at the tap, we have to apply the relationship between pressure and density:

[tex]P=\rho *g*h[/tex]

where ρ = density

g = acceleration due to gravity = 9.8 m/s^2

h = height

Therefore, the pressure of the kerosene at the tap is:

[tex]\begin{gathered} P=800*9.8*1.5 \\ P=11,760\text{ }N\/m^2 \end{gathered}[/tex]

That is the answer.

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