Explanation
We are given the following:
• 13 balls numbered 1 through 13 placed in a bucket.
We are required to determine the probability of randomly drawing two balls numbered 12 and 2 without replacement, in that order.
This is achieved thus:
The probability of randomly selecting a ball numbered 12 from the bucket is:
[tex]Pr.(12)=\frac{1}{13}[/tex]The probability of randomly selecting 2 from the bucket after the first selection is:
[tex]Pr.(2)=\frac{1}{12}[/tex]Therefore, the probability of randomly selecting two balls numbered 12 and 2 is:
[tex]\begin{gathered} Pr.=\frac{1}{13}\times\frac{1}{12} \\ Pr.=\frac{1}{156} \end{gathered}[/tex]Hence, the answer is:
[tex]\frac{1}{156}[/tex]