ANSWER:
[tex]\begin{gathered} \frac{3y-3}{1-y}=-3 \\ y\ne1 \end{gathered}[/tex]
STEP-BY-STEP EXPLANATION:
Step 1 of 2:
We have the following expression
[tex]\frac{3y-3}{1-y}[/tex]
We factor in order to reduce to the lowest terms, like that:
[tex]\frac{3\cdot(y-1)}{1-y}=\frac{3\cdot(y-1)}{-1\cdot(y-1)}=\frac{3}{-1}=-3[/tex]
Step 2 of 2:
In this case the only restriction is when the denominator is equal to 0, therefore we set the denominator equal to 0 and solve for y
[tex]\begin{gathered} 1-y=0 \\ -y=-1 \\ y=1 \end{gathered}[/tex]
Therefore y can't take the value of 1
