1.
On the first draw, 2 out of the 10 balls are blue. Therefore, the probability of choosing a blue ball is:
[tex]\frac{2}{10}\rightarrow\frac{1}{5}[/tex]On the second draw, 2 out of the 10 balls are blue, because the drawn blue ball is replaced. Therefore, the probability of choosing a second blue ball is:
[tex]\frac{2}{10}\rightarrow\frac{1}{5}[/tex]The probability of choosing 2 blue balls in a row, with replacement between the first and second draw, is:
[tex]\frac{1}{5}\cdot\frac{1}{5}=\frac{1}{25}[/tex]Or 4%
ANSWER 1:
[tex]\frac{1}{25}[/tex]2.
On the first draw, 5 out of the 10 balls are white. Therefore, the probability of choosing a white ball is:
[tex]\frac{5}{10}\rightarrow\frac{1}{2}[/tex]On the second draw, 4 out of the 9 remaining balls are white. Remember that the white ball drawn isn't replaced.
Therefore, the probability of choosing a second white ball is:
[tex]\frac{4}{9}[/tex]Thereby, the probability of choosing 2 white balls in a row, without replacement between the first and second draw, is:
[tex]\frac{1}{2}\cdot\frac{4}{9}=\frac{4}{18}\rightarrow\frac{2}{9}[/tex]Or about 22%
ANSWER 2:
[tex]\frac{2}{9}[/tex]