A box contains 3 red balls 2 blue balls and 5 white balls a ball is selected and it’s color noted a second ball is selected an it’s color noted find the probability of each of these. 1. P(selecting 2 blue balls) with replacement between the first and second draw2. P(selecting 2 white balls) without replacement between the first and second drawAnswer the questions below show all your work and make sure your answer is in lowest fraction form.

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1.

On the first draw, 2 out of the 10 balls are blue. Therefore, the probability of choosing a blue ball is:

[tex]\frac{2}{10}\rightarrow\frac{1}{5}[/tex]

On the second draw, 2 out of the 10 balls are blue, because the drawn blue ball is replaced. Therefore, the probability of choosing a second blue ball is:

[tex]\frac{2}{10}\rightarrow\frac{1}{5}[/tex]

The probability of choosing 2 blue balls in a row, with replacement between the first and second draw, is:

[tex]\frac{1}{5}\cdot\frac{1}{5}=\frac{1}{25}[/tex]

Or 4%

ANSWER 1:

[tex]\frac{1}{25}[/tex]

2.

On the first draw, 5 out of the 10 balls are white. Therefore, the probability of choosing a white ball is:

[tex]\frac{5}{10}\rightarrow\frac{1}{2}[/tex]

On the second draw, 4 out of the 9 remaining balls are white. Remember that the white ball drawn isn't replaced.

Therefore, the probability of choosing a second white ball is:

[tex]\frac{4}{9}[/tex]

Thereby, the probability of choosing 2 white balls in a row, without replacement between the first and second draw, is:

[tex]\frac{1}{2}\cdot\frac{4}{9}=\frac{4}{18}\rightarrow\frac{2}{9}[/tex]

Or about 22%

ANSWER 2:

[tex]\frac{2}{9}[/tex]