ANSWER:
[tex]2\cdot g(4)-3\cdot f(-1)=1[/tex]
STEP-BY-STEP EXPLANATION:
We have the following functions:
[tex]\begin{gathered} f\mleft(x\mright)=3x^2-2x \\ g\mleft(x\mright)=2\sqrt{x}+4 \end{gathered}[/tex]
We calculate in each case the part corresponding to each function and then perform the subtraction:
[tex]\begin{gathered} 2\cdot g(4)=2\cdot(2\sqrt[]{4}+4)=2\cdot(2\cdot2+4)=2\cdot8=16 \\ 3\cdot f(-1)=3\cdot(3\cdot(-1)^2-2\cdot(-1))=3\cdot(3\cdot1+2)=3\cdot5=15 \\ \text{ Therefore:} \\ 2\cdot g(4)-3\cdot f(-1)=16-15=1 \end{gathered}[/tex]
