Answer:
Plotting the graph by selecting the two points using the parabola tool.
Explanation:
Given the function;
[tex]h(x)=-x^2+3[/tex]
To find the vertex, it is the lowest or the highest point on the parabola.
[tex]\begin{gathered} At\text{ the vertex h'(x)=0} \\ h^{\prime}(x)=-2x=0 \\ -2x=0 \\ x=0 \end{gathered}[/tex]
So, the vertex will be at x=0;
[tex]\begin{gathered} h(0)=-0^2+3 \\ h(0)=3 \\ (0,3) \end{gathered}[/tex]
We can then identify one other point on the parabola;
[tex]\begin{gathered} at\text{ x=3} \\ h(x)=-x^2+3 \\ h(3)=-(3)^2+3 \\ h(3)=-9+3 \\ h(3)=-6 \\ (3,-6) \end{gathered}[/tex]
Plotting the graph by selecting the two points using the parabola tool.
