Given:
The function
[tex]f(x)=4-7x+16x^2[/tex]
Required:
Calculate the given functions.
Explanation:
The calculation is as:
[tex]\begin{gathered} f(a)=4-7a+16a^2 \\ f(a+h)=4-7(a+h)+16(a+h)^2 \\ =4-7a-7h+16(a^2+h^2+2ah) \\ =4-7a-7h+16a^2+16h^2+32ah \\ Now, \\ \frac{f(a+h)-f(a)}{h}=\frac{4-7a-7h+16a^2+16h^2+32ah-4+7a-16a^2}{h} \\ =\frac{-7h+16h^2+32ah}{h} \\ =-7+16h+32a \end{gathered}[/tex]
Answer:
answered the question.
