Answer
b. 5
Explanation
The moles of CaCO3 present in 500 grams of CCO3 can be calculated using the mole formula.
[tex]Mole=\frac{Mass}{Molar\text{ }mass}[/tex]Molar mass of CaCO3 100 g/mol
Putting mass = 500 g and molar mass = 100 g/mol into the mole formula, we have,
[tex]Mole=\frac{500\text{ }g}{100\text{ }g\text{/}mol}=5\text{ }moles[/tex]The moles of CaCO3 resent in 500 grams of CacCO3 = 5 moles
