Net energy of reaction = -5412kJ
Reaction is exothermic
Given the following reaction;
[tex]2N≡N+2O=O\rightarrow2N=O+2N=O[/tex]The net energy of the reaction is expressed as:
[tex]\triangle H=H_p-H_r[/tex]Determine the enthalpy change of the product
[tex]\begin{gathered} H_p=2(-631)+2(-631) \\ H_p=-1262-1262 \\ H_p=-2524kJ \\ \end{gathered}[/tex]Determine the enthalpy change for the reactant
[tex]\begin{gathered} H_r=2(946)+2(498) \\ H_r=1892+996 \\ H_r=2888kJ \end{gathered}[/tex]Determine the net energy for the reaction
[tex]\begin{gathered} \triangle H=-2524kJ-2888kJ \\ \triangle H=-5412kJ \end{gathered}[/tex]Since the net energy of the reaction is negative, hence the reaction will be exothermic (energy is liberated to the surrounding)