Given data:
Initial population = 1,500
For every 33 minutes the population doubles.
The first step will be to write a function that models this statement
The model is given as
[tex]\begin{gathered} y=1500(2^{\frac{t}{33}})^{} \\ \text{Where t is the initial time},\text{ y= final population} \\ \end{gathered}[/tex]The next step will be to find the population of the bacteria at time t=66 minutes.
This will be obtained by substituting t=66 into the equation
[tex]y=1500(2^{\frac{66}{33}})[/tex][tex]y=1500(2^2)[/tex]=>
[tex]y=1500(4)[/tex]=>
[tex]y=6000[/tex]Therefore the population of the bacteria after 66 minutes will be 6,000
