[tex]\begin{gathered} \text{ The area of a sector can be calculated by the formula} \\ \text{ A=}\frac{\theta}{360}\text{ x }\pi r^2 \\ \text{ Where }\theta\text{ = angle subtended by the sector at the center} \\ \text{ r= radius of the sector} \end{gathered}[/tex][tex]\begin{gathered} \text{ For this question, } \\ \theta=45^0,\text{ r= 9m} \\ \text{ A = }\frac{45}{360}\text{ x 3.14 x 9 x 9} \\ \text{ A= 31.7925m}^2 \\ A=31.8m^2\text{ (nearest tenth)} \end{gathered}[/tex]
The area of the sector is 31.8m^2 ( nearest tenth)
