ANSWER:
0.9 N
STEP-BY-STEP EXPLANATION:
Given:
Charges (q1 and q2) = 0.00005 C
Distance (d) = 5 m
We use Coulomb's law to calculate the electric force between the charges:
[tex]F=k\cdot\frac{q_1\cdot q_2}{d^2}[/tex]We substitute each value and obtain the electric force, like this:
[tex]\begin{gathered} F=9\cdot10^9\cdot\frac{(0.00005)(0.00005)}{5^2} \\ \\ F=0.9\text{ N} \end{gathered}[/tex]The force between both forces is 0.9 N
