Please help me solve this problem. I am looking for the coordinates for A’, B’ and C’

ANSWER
• A'(-10, 0)
,• B'(-6, 2)
,• C'(-8, -2)
EXPLANATION
This vector is written as:
[tex]\langle-6,-4\rangle[/tex]This means that if we use this vector to translate a figure, we have to move each point of the figure 6 units to the left and 4 units down.
The vertices of triangle ABC are:
[tex]\begin{gathered} A(-4,4) \\ B(0,6) \\ C(-2,2) \end{gathered}[/tex]To each x-coordinate we have to subtract 6 units in order to translate these points 6 units to the left, and to each y-coordinate we have to subtract 4 units in order to translate these points 4 units down:
[tex]\begin{gathered} A^{\prime}(-4-6,4-4)=(-10,0) \\ B^{\prime}(0-6,6-4)=(-6,2) \\ C^{\prime}(-2-6,2-4)=(-8,-2) \end{gathered}[/tex]