Given, initial velocity in the y-direction, vi=2.88 m/s
The acceleration of the runner, a=0.350 m/s²
The angle at which she is running, θ=-52.0°
The x-component of the acceleration is
[tex]a_x=a\times\cos \theta[/tex]
On substituting the known values,
[tex]a_x=0.350\times\cos -52.0^0=0.215m/s^2[/tex]
And the y-component of the acceleration is,
[tex]a_y=a\times\sin \theta[/tex]
On substituting the known values,
[tex]a_y=0.350\times\sin (-52.0)=-0.276m/s^2[/tex]
We can see that only table B has these values.
Therefore the correct answer is option B
