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Which equation describes the line with slope 5 that contains the point (-1,4)?O A. y+ 4 = 5(x+1)B. y - 4 = 5(x - 1)O c. y+ 4 = 5(x - 1)O D. y - 4 = 5(x+1)P

Which equation describes the line with slope 5 that contains the point 14O A y 4 5x1B y 4 5x 1O c y 4 5x 1O D y 4 5x1P class=

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Answer

D

[tex]y-4=5(x+1)[/tex]

Step-by-step explanation

The equation of a line in point slope form is

[tex]y-y_1=m(x-x_1)[/tex]

where m is the slope and (x₁, y₁) is a known point.

Substituting m = 5 and the point (-1, 4), we get:

[tex]\begin{gathered} y-4=5(x-(-1)) \\ y-4=5(x+1) \end{gathered}[/tex]

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