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A compound has an empirical formula of CH2.What is its molecular formula, if its molarmass is 70,13 g/mol?(C=12.01 amu, H=1,008 amu)BC3H6C5H10

A compound has an empirical formula of CH2What is its molecular formula if its molarmass is 7013 gmolC1201 amu H1008 amuBC3H6C5H10 class=

Respuesta :

Answer:

The molecular formula is C5H10. (B)

Explanation:

1st) It is necessary to calculate the molar mass of the empirical formula:

C: 12.01

H: 1.008

CH2 molar mass= (1x12.01) + (2x1.008)

CH2 molar mass= 14.026g/mol

2nd) We have to divide the molar mass of the compound (70.13g/mol) by the molar mass of the empirical formula (14.026g/mol):

70.13/14.026=5

Finally, we have to multiply the empirical formula by 5, so the molecular formula is C5H10.

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