Given the following question:
[tex]\frac{2x^2-4x+3}{-2x}[/tex][tex]\begin{gathered} \frac{2x^2-4x+3}{-2x} \\ 2x^2\div-2x=-x \\ -x+\frac{-4x+3}{-2x} \\ -4x\div-2x=2 \\ -x+2+\frac{3}{-2x} \\ -x+2-\frac{3}{2x} \end{gathered}[/tex]Your answer is "-x + 2 - 3 / 2x"
