Given: The bearing and distance of Maria and an antenna
To Determine: The height of the antenna from the given information
Solution
From the given information, the diagram below can be deduced
From the diagram above, the height of the antenna is TB
Using SOH CAH TOA
[tex]\begin{gathered} tan38^0=\frac{TC}{EC} \\ EC=BG=200ft \\ SO, \\ tan38^0=\frac{TC}{200} \\ TC=200\times tan38^0 \end{gathered}[/tex][tex]\begin{gathered} TC=156.257ft \\ TB=TC+CB \\ EG=CB=5ft \\ TB=156.257+5 \\ TB=161.257ft \\ TB\approx161ft \end{gathered}[/tex]Hence, the height of the antenna is 161ft
