Two dice are rolled; find the favor of rolling a sum:a. Equaling 8b. greater than 6c. Less than or equal to 9d. that is an odd number

When two dice are rolled, there are 36 possibilities. These can be found by calculating the number of counts.
We are required to find the favor of rolling a sum, which is similar to saying the probability of rolling a given sum.
Recall that the probability of an event occurring is given as:
[tex]\text{Probability = }\frac{Number\text{ of required outcomes}}{\text{Total Number of possible outcomes}}[/tex](a) Sum equaling 8
[tex]\text{Probability = }\frac{5}{36}[/tex](b) Greater than 6
[tex]\begin{gathered} \text{Probability = probability of 7 + probability of 8 + probability of 9 + probability of 10 + probability of 11 + probability of 12} \\ =\text{ }\frac{6\text{ + 5 + 4 + 3 + 2 + 1}}{36} \\ =\text{ }\frac{21}{36} \\ =\text{ }\frac{7}{12} \end{gathered}[/tex](c) Less than or equal to 9
[tex]\begin{gathered} \text{Probability = 1 - Probability of a sum greater than 9} \\ =\text{ 1 - (Probability of 10 + Probablity of 11 + Probability of 12)} \\ =\text{ 1 - }\frac{6}{36} \\ =\text{ }\frac{30}{36} \\ =\text{ }\frac{5}{6} \end{gathered}[/tex](d) That is an odd number
Odd numbers are 1, 3 , 5 , ...
[tex]\begin{gathered} There\text{ are 18 odd numbers} \\ \text{Probability = }\frac{18}{36} \\ =\text{ }\frac{1}{2} \end{gathered}[/tex]