Answer:
The standard form of a hyperbola is given below as
[tex]\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1 \\ around\text{ the origin,we will have the equation to be} \\ \frac{x^2}{a^2}-\frac{y^2}{b^2}=1 \end{gathered}[/tex]
Given that the equation of the hyperbola is given below as
[tex]\frac{y^2}{6^2}-\frac{x^2}{8^2}=1[/tex]
Therefore,
The standard form of a hyperbola should be left like that
Except if asked otherwise in an objective question with options
