EXPLANATION:
-To solve a multiplication of polynomials we must multiply the monomial outside the parentheses by each of the monomials that make up the polynomial within the parentheses.
-We must remember that when multiplying two powers with the same base, the exponents are added,
The exercise is as follows:
[tex]\begin{gathered} 9ab^5(a^2b^4-10a^3b+5ab-3)^{} \\ (9a^3b^9)-(90a^{4^{}}b^6)+(45a^2b^6)-(27ab^5) \\ answer\colon9a^3b^9-90a^4b^6+45a^2b^6-27ab^5 \end{gathered}[/tex]