The equation above is an equation of a circle
The equation can be written as follow.
[tex]\begin{gathered} (x+3)^2+(y+1)^2=3^2 \\ \text{Next compare with } \\ (x-a)^2+(y-b)^2=r^2 \\ r\text{ is the radius and ( a, b ) is the center.} \end{gathered}[/tex]Therefore,
Radius r = 3 and center = (-3, -1)
