The accompanying diagram shows the path of a cart traveling on a circular track of radius 2.40 meters. The cart starts at point A and stops at point B, moving in a counterclockwise direction. What is the length of minor arc AB, over which the cart traveled, to the nearest tenth of a meter?

The accompanying diagram shows the path of a cart traveling on a circular track of radius 240 meters The cart starts at point A and stops at point B moving in a class=

Respuesta :

when you have a circumference that has a radio of 1 unit we can say that 360° are going to be 2pi, or 180° is pi.

the formula for the arclength will be

[tex]S=r\Theta[/tex]

now we have to pass the 165° to radians, and that is why we use the 180°=pi

[tex]\begin{gathered} 180=\pi \\ 165=x \\ x=\frac{165}{180}\pi=\frac{11}{12}\pi \end{gathered}[/tex]

now that you have the angle in radians, multiply it by the radio.

[tex]\begin{gathered} S=2.40\cdot(\frac{11}{12}\pi) \\ S=\frac{11}{5}\pi\approx6.9m \end{gathered}[/tex]