complete the remainder of the table for the given function rule: y= - x/3 + 2

We need to evalute the function at x=0, x=3 and x=6.
For instance, at x=-3 we have
[tex]\begin{gathered} y=-\frac{-3}{3}+2 \\ y=1+2 \\ y=3 \end{gathered}[/tex]At x=0, we obtain
[tex]\begin{gathered} y=-\frac{0}{3}+2 \\ y=2 \end{gathered}[/tex]At x=3, we have
[tex]\begin{gathered} y=-\frac{3}{3}+2 \\ y=-1+2 \\ y=1 \end{gathered}[/tex]and finally, at x=6, we have
[tex]\begin{gathered} y=-\frac{6}{3}+2 \\ y=-2+2 \\ y=0 \end{gathered}[/tex]Hence, the table is given by