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A force of 60. newtons is applied to a rope to pull a sled across a horizontal surface at a constant velocity. The rope is at an angle of 30. Degrees above the horizontal.8-9. Calculate the magnitude of the component of the 60.-newton force that is parallel to the horizontal surface. [Show all work, including the equation and substitution with units.] [2]

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ANSWER:

51.96 N

STEP-BY-STEP EXPLANATION:

The horizontal component of the pulling force of Force is FAx since the axis is horizontal, therefore:

[tex]\begin{gathered} F_x=F\cdot\cos _{}\theta \\ \text{ replacing} \\ F_x=60\cdot\cos 30 \\ F_x=51.96\text{ N} \end{gathered}[/tex]

The magnitude of the component of the 60 newton is 51.96 N

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