Step 1
State a trigonometric identity that can be used to find the value of x
[tex]\begin{gathered} \text{Toa} \\ \text{where} \\ T\text{ = tan} \\ o=\text{ opposite}=3 \\ a\text{ = adjacent}=x \\ \text{and written as} \\ \text{Tan 30 =}\frac{opposite}{\text{adjacent}} \end{gathered}[/tex]Step 2
Substitute and find the value of x
[tex]\begin{gathered} \text{Tan}30\text{ =}\frac{3}{x} \\ Tan\text{ 30 = }\frac{1}{\sqrt[]{3}} \end{gathered}[/tex]Hence,
[tex]\begin{gathered} \frac{1}{\sqrt[]{3}}=\frac{3}{x} \\ x\text{ = 3}\sqrt[]{3} \end{gathered}[/tex]Therefore x = 3√3
