Explanation
the speed of an object is given by:
[tex]\text{speed}=\text{ }\frac{dis\tan ce}{\text{time taken}}[/tex]then
Step 1
Let
[tex]\begin{gathered} \text{Time}=2.6\text{ s} \\ \text{distance}=\text{ 2(}3.85\times10^8)=7.7\times10^8 \end{gathered}[/tex]Now, replace
[tex]\begin{gathered} \text{speed}=\text{ }\frac{dis\tan ce}{\text{time taken}} \\ \text{speed}=\text{ }\frac{7.7\times10^8\text{ m}}{2.6\text{ s}} \\ \text{speed}=2.96\times\text{ }10^8\text{ }\frac{\text{m}}{s} \end{gathered}[/tex]so, the answer is
[tex]speed_c=2.96\times\text{ }10^8\text{ }\frac{\text{m}}{s}[/tex]I hope this helps you
