Answer:
The length of the hypotenuse is;
[tex]26\text{ units}[/tex]
Explanation:
Given the triangle in the attached image.
The length of the two legs given as;
[tex]\begin{gathered} a=10 \\ b=24 \end{gathered}[/tex]
Applying Pythagorean thereom;
[tex]\begin{gathered} a^2+b^2=c^2 \\ c=\sqrt[]{a^2+b^2} \end{gathered}[/tex]
substituting the given values;
[tex]\begin{gathered} c=\sqrt[]{10^2+24^2} \\ c=\sqrt[]{100+576} \\ c=\sqrt[]{676} \\ c=26 \end{gathered}[/tex]
Therefore, the length of the hypotenuse is;
[tex]26\text{ units}[/tex]
