Find the length of the altitude of an isosceles triangle with a 41° base angle and a base 38 cm long. Round your answer to the nearest tenth.

Respuesta :

Let's draw a picture of our problem:

From our figure we have the following right triangle:

so, in order to get the altitute (height) of our isosceles triangle, denoted by h, we can use a trigonometric function .

If we apply the tangent function, we have

[tex]\tan (41)=\frac{h}{19}[/tex]

then, by moving 19 to the left hand side, we get

[tex]19\cdot\tan (41)=h[/tex]

which gives

[tex]\begin{gathered} h=19\cdot\tan (41)\text{ cm} \\ h=19\cdot(0.8693)\text{ cm} \\ h=16.52\text{ cm} \end{gathered}[/tex]

Therefore, by rounding down to the nearest tenth, the altitude is equal to 16.5 centimeters

Ver imagen EkerW448293
Ver imagen EkerW448293