Respuesta :
The balanced equation of reaction they describe is the following:
NaOH + KHP → KNaP + H2O
By stoichiometry, we have that the ratio NaOH and KHP is one to one, which means that if we have n moles of KHP we will need the same n moles NaOH.
Now, let's determine the moles of KHP using its molecular mass:
[tex]\begin{gathered} \text{Moles of KHP = g of KHP}\times\frac{1molKHP}{204.22gKHP} \\ \text{Moles of KHP = 0.322g of KHP}\times\frac{1molKHP}{204.22gKHP} \\ \text{Moles of KHP = }1.577\times10^{-3}molKHP \end{gathered}[/tex]Therefore, we must add 1.577x10^-3 moles of NaOH. The molarity is defined as:
[tex]\begin{gathered} \text{Molarity = }\frac{\text{Moles of solute}}{L\text{ of solution}} \\ \text{Molarity}=\text{ }\frac{\text{1.577}\times10^{-3}mol}{19.20mL\times\frac{1L}{1000mL}} \\ \text{Molarity}=0.082M \end{gathered}[/tex]The molarity of NaOH solution is 0.082M
