Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.A charitable organization in Livingston is hosting a black tie benefit. Yesterday, the organization sold 21 regular tickets and 38 VIP tickets, raising $5,228. Today, 44 regular tickets and 58 VIP tickets were sold, bringing in a total of $8,792. How much do the different ticket types cost?

Respuesta :

Let's use the variable x to represent the price of a regular ticket and the variable y to represent the price of a VIP ticket.

If 21 regular tickets and 38 VIP tickets cost $5228, we can write the following equation:

[tex]21x+38y=5228[/tex]

If 44 regular tickets and 58 VIP tickets cost $8792, we can write the following equation:

[tex]44x+58y=8792[/tex]

Now, to solve this system of equations, let's solve the first equation for x and then use its value in the second equation:

[tex]\begin{gathered} 21x=5228-38y \\ x=\frac{5228-38y}{21} \\ \\ 44\cdot(\frac{5228-38y}{21})+58y=8792 \\ 10953.9-79.619y+58y=8792 \\ -21.619y=8792-10953.9 \\ -21.619y=-2161.9 \\ y=100 \\ \\ x=\frac{5228-3800}{21} \\ x=\frac{1428}{21} \\ x=68 \end{gathered}[/tex]

Therefore the price of a regular ticket is $68 and the price of a VIP ticket is $100.