In order to answer this question, we need to find the volume of one cubic box and the volumeof the storage bin.
The volume of the cubic box is given by
[tex]V_c=(\frac{1}{2})^3[/tex]which gives
[tex]V_c=\frac{1}{8}ft^3[/tex]On the other hand, the volume of the storage bin is given by
[tex]V_s=2\frac{1}{2}\times2\times2[/tex]but we need to convert first the mixed fraction form into a simple fraction form, that is
[tex]2\frac{1}{2}=\frac{2\times2+1}{2}=\frac{5}{2}[/tex]then, its volume is
[tex]\begin{gathered} V_s=\frac{5}{2}\times2\times2 \\ V_s=10ft^3 \end{gathered}[/tex]Now, we need to compare our last volume with the volume of the cubic box, that is,
[tex]\frac{V_s}{V_c}=\frac{10}{\frac{1}{8}}=80[/tex]this means that Alan can keep 80 cubic boxes into the storage bin