Given:
A 6 sided die is rolled.
[tex]S=\mleft\lbrace1,2,3,4,5,6\mright\rbrace[/tex][tex]n(s)=6[/tex]Let A be the event of getting a number less than 6.
[tex]n(A)=5[/tex][tex]P(A)=\frac{n(A)}{n(S)}[/tex][tex]P(A)=\frac{5}{6}[/tex][tex]P(A)=0.833[/tex]Therefore, probability of getting a number less than 6 is 0.833
