Given the equation:
[tex]\log _2(7x)+\log _22=1[/tex]As we know: log a + log b = log (ab)
So,
[tex]\begin{gathered} \log _2(7x\cdot2)=1 \\ \log _2(14x)=\log _22 \\ \\ 14x=2 \\ x=\frac{2}{14} \\ \\ x=\frac{1}{7} \end{gathered}[/tex]So, the answer will be x = 1/7
