The expression for the equation of the line with the given two coordinates
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]Given pair of coordinates : (8,-4) & (6,-5)
Substitute the value and simplify
[tex]\begin{gathered} y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ \text{Substitute x}_1=8,x_2=6,y_1=(-4),y_2=(-5) \\ y-(-4)=\frac{-5-(-4)}{6-8}(x-8) \\ y+4=\frac{-5+4}{-2}(x-8) \\ y+4=\frac{1}{2}(x-8) \\ y=\frac{x}{2}-\frac{8}{2}-4 \\ y=\frac{x}{2}-4-4 \\ y=\frac{x}{2}-8 \\ 2y=x-16 \\ x-2y-16=0 \end{gathered}[/tex]Answer : Equation of line is : x-2y-16=0
